Question: What is the percent of the unprotonated form of ammonia (Kb NH3 = 1.74 x 10-5) in a solution at pH 8.68? What is the percent of the unprotonated form of ammonia ( Kb NH 3 = 1 . 7 4 x 1 0 - 5 ) in a solution at pH
kb(nh3)= 1.76×10-5 a. 9.23 b. 3.69 c. Your solution’s ready to go! Our expert help has broken down your problem into an easy-to-learn solution you can count on.
8. Use the Henderson-Hasselbalch equation to calculate the pH of each solution. a solution that is 0.18 M in HCHO2 and 0.12 M in NaCHO2 (Ka(HCHO2)=1.8×10−4) Express your answer to two decimal places. Part B a solution that is 0.14 M in NH3 and 0.20 M in NH4Cl (Kb(NH3)=1.76×10−5) Express your answer to two decimal places. 3.
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kb for nh3|Solved 1. Given that Kb of NH3 is 1.8 X 10
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